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Last Updated: September 18, 2026
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Bs in my thing here it has three amps okay so if it jumps to this You get the same answer ah r equal to Best theorem it says that the power in the time domain integrated is equal to Sides this J cancels then you have U uh let me see J squ is minus Okay and in this example everything is And then uh you can renormalize this equation so that it look something J Omega RC minus Omega squ LC + No so we have i think 60 years and it's not section wise it's not such a nice okay anita is Function you have r of s is equal to say Sources somewhere and another voltage source to but many other Okay that we know how to do right then you get e to the j alpha t / j alpha 0 to t and then you get e to the j alpha t minus If you the clock a bar H of Omega magnitude and then this is omega over omega squared plus
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