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UIUC ECE 210 L48-2
UIUC ECE 210 25-2
UIUC ECE 210 20-2
UIUC ECE 210 3-1
UIUC ECE 210 17-2
UIUC ECE 210 7-2
UIUC ECE 210 24-2
UIUC ECE 210 L26-2
UIUC ECE 210 10-2
UIUC ECE 210 L28-2
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Last Updated: September 18, 2026
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Summary
... current flowing that arm because this current is flowing in that arm what is this current flowing down here i ... progresses the rate of change of current is going to be very slow and this Yeah just a factor of two there so it can be one over l one over l is two okay so first we have an input i sub Okay minus dot dot dot s f of n minus No this is a sum oh it's a sum it's a song minus so if you look at the summon what you have a 10 to Sides this J cancels then you have U uh let me see J squ is minus one so if this cancels each other then you have uh J is = - ... and then the second term would be four of f e to the j omega t and then the right hand side will just be ... in order to make the output come out correct 0.5 okay this has to be evaluated at Omega equal to 0.5 ... form it looks something this f of 0 plus n is to the ... was just 1.5 i know obviously i didn't know why the feed ... high before and then you have the rest of the prompt which is written according to the textbook is