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Okay no question Then um let's figure out how we can get a formula such as this He is 2 pi over n Omega naught largest Okay that we know how to do right then you get e to the j alpha t / j alpha 0 to t and then you get e to the j alpha t minus No so we have i think 60 years and it's not section wise it's not such a nice okay anita is And then uh you can renormalize this equation so that it look something J Omega RC minus Omega squ LC + Fact and I can work out the detail for you if you want to work out BC okay BC is equal to We have another voltage source here and then this is given to be minus two volts so here and we have If you the clock a bar H of Omega magnitude and then this is omega over omega squared plus Okay and in this example everything is Okay and typical values digital values is that ro is about Okay so this will retransform to that and then you're given that the input ft is a sine of 2 psi t and f of omega must be equal to ... Square Omega t with does anybody remember the trigonometric identity for cosine of square of Thea I have the graded homework this here
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