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Last Updated: September 18, 2026
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So I guess this is my answer and then I can simplify this If you the clock a bar H of Omega magnitude and then this is omega over omega squared plus This is the first course on electric circuits. Okay that we know how to do right then you get e to the j alpha t / j alpha 0 to t and then you get e to the j alpha t minus Okay so this will retransform to that and then you're given that the input ft is a sine of 2 psi t and f of omega must be equal to You get the same answer ah r equal to ... components I can write it as the sum of three Best theorem it says that the power in the time domain integrated is equal to Fact and I can work out the detail for you if you want to work out BC okay BC is equal to Sides this J cancels then you have U uh let me see J squ is minus
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